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Home/ Questions/Q 4249040
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Editorial Team
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Editorial Team
Asked: May 21, 20262026-05-21T04:20:36+00:00 2026-05-21T04:20:36+00:00

This works div{ -ms-transform: rotate(30deg); } And following does not $(div).css(-ms-transform,rotate(30deg)); Any ideas why,

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This works

div{
    -ms-transform: rotate(30deg);
}

And following does not

$("div").css("-ms-transform","rotate(30deg)");

Any ideas why, and how to fix it?
Same thing works good on all other browsers, but not on IE.
Ofcourse, only IE9 supports it. Older versions dont.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-21T04:20:37+00:00Added an answer on May 21, 2026 at 4:20 am

    The dash (‘-‘) in the property is invalid for use in scripting. You should use msTransform instead.

    By the way: though a number of browsers do understand and parse css like style[‘background-color’] from scripting, afaik Firefox doesn’t. Furthermore I think JQuery .css(...) transforms properties like 'background-color' to their DOM-scripting equivalent ('backgroundColor' in this case) before parsing it.

    To be complete: JQuery.css indeed transforms dashed properties to camelCase. Here’s a representation of the JQuery.css-internals with the string '-ms-transform':

    var fcamelCase = function( all, letter ) {
            return letter.toUpperCase();
        };
    var rdashAlpha = /-([a-z])/ig;
    // JQuery.css does a replace operation with these variables 
    // on the raw property string:
    alert('-ms-transform'.replace(rdashAlpha,fcamelCase)); //=> msTransform
    

    So that’s why $("div").css("-ms-transform","rotate(30deg)") doesn’t work in IE9. IE9 expects: msTransform.

    Why then, does $("div").css("-moz-transform", "rotate(-90deg)") work in Firefox? Because Mozilla evidently decided to use complete CamelCase for their -moz-[properties], so the MozTransform scripting style property is valid (and, by the way, mozTransform isn’t … really).

    It’s all to the browser then, nothing new under the digital sun.

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