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Home/ Questions/Q 7822909
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Editorial Team
  • 0
Editorial Team
Asked: June 2, 20262026-06-02T08:04:09+00:00 2026-06-02T08:04:09+00:00

This works fine if I don’t check both boxes. Not sure how to fix

  • 0

This works fine if I don’t check both boxes. Not sure how to fix it.

$(".home-check").live('click', function() {
if ($(".home-check").is(':checked')) {
    var ident = $(this).attr('id');
    $('.' + ident).hide();

} else {
    var identt = $(this).attr('id');
    $('.' + identt).show();
}
});​
<p><input class="home-check" id="water" type="checkbox" name="gethired" />Fire - Only Show Fire</p>
<p><input class="home-check" id="fire" type="checkbox" name="hire" />Water - Only Show Water</p>

<li class="fire">Fire</li>
<li class="water">Water</li>
<li class="fire">Fire</li>
<li class="water">Water</li>
<li class="fire">Fire</li>
<li class="water">Water</li>

http://jsfiddle.net/cip691/AeyAL/2/

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-02T08:04:11+00:00Added an answer on June 2, 2026 at 8:04 am

    Try this instead:

    $(".home-check").on('click', function() {
        var li_class = '.' +  this.id;    
        $(li_class).toggle();
    });
    

    ​
    Do not use live in this case it’s not necessary, use toggle instead of show and hide = less code to write ;).

    And instead of

    $(this).attr('id');
    

    use:

    this.id
    

    It will be quicker !

    Hope it was useful !

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