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Home/ Questions/Q 4322266
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Editorial Team
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Editorial Team
Asked: May 21, 20262026-05-21T08:51:05+00:00 2026-05-21T08:51:05+00:00

This works: $.fn.center = function () { this.css(position, absolute); this.css(top, ($(window).height() – this.height()) /

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This works:

$.fn.center = function () {
    this.css("position", "absolute");
    this.css("top", ($(window).height() - this.height()) / 2 + $(window).scrollTop() + "px");
    this.css("left", ($(window).width() - this.width()) / 2 + $(window).scrollLeft() + "px");
    return this
};
$('#container').center();

.. but the element stays in the same position if the window is resized, how do I center it with the resize too?

Thanks

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-21T08:51:05+00:00Added an answer on May 21, 2026 at 8:51 am

    You would need to execute that code in the window resize event. But, if the browser is resized this event fires huge! So it’s in general a good idea to create a little “balancer”.

    $(window).bind('resize', function() {
        var that = this;        
    
        if(!('balancer' in that) ) {
            that.balancer = setTimeout(function() {
                $('#container').center();
                delete that.balancer;
            }, 200);
        }
    });
    

    This will absorb the many events that are fired when resizing the browser window. In fact, it only calls the .center() at a maximum of 200ms. You probably should even increase that value and cache the node reference to the #container element.

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