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Home/ Questions/Q 8830943
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T08:12:16+00:00 2026-06-14T08:12:16+00:00

This works for ${VAR}: Pattern.compile(\\$\\{(.+?)\\}); But I am struggling to format it so that

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This works for ${VAR}:

Pattern.compile("\\$\\{(.+?)\\}"); 

But I am struggling to format it so that it also accepts $VAR to the next word boundry (\b). Because the text can be

$FIRSTVAR.${SECONDVAR}LITERAL

and then I want to detect both $FIRSTVAR and ${SECONDVAR} and if the first is “X” and the second if “Y”, I want to replace it to X.YLITERAL. The template uses both $VAR and ${VAR} styles, prefers the former if the var is followed with a non-word character but uses the latter if it is (just like in the example I gave above).

I tried

Pattern.compile("\\$(\\{|)(.+?)(\\}|\b})");

But that matches FIRSTVAR.${SECONDVAR as group(2). So it’s not good.
Thanks in advance

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  1. Editorial Team
    Editorial Team
    2026-06-14T08:12:17+00:00Added an answer on June 14, 2026 at 8:12 am

    I would write:

    Pattern.compile("\\$(?:(\\w+)|\\{(\\w+)\\})")
    

    Naturally, this means that either matcher.group(1) or matcher.group(2) will be the variable-name — the other will be null — so you’ll have to check both.

    Another, less-robust option is to write:

    Pattern.compile("\\$\\{?(\\w+))\\}?")
    

    but then it would replace e.g. $SECONDVAR} with Y rather than with Y}.


    Edited to add: If you’re using Java 7, I think you should be able to write

    Pattern.compile("\\$(?:(?<varname>\\w+)|\\{(?<varname>\\w+)\\})")
    

    and then retrieve the variable-name using matcher.group("varname"). (I haven’t tested that in Java, because I only have Java 6 handy, and Java 6 doesn’t support named capture-groups. But it does work in Perl.) See “Group name” in the java.util.regex.Pattern javadoc and the javadoc for java.util.regex.Matcher.group(java.lang.String).

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