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Home/ Questions/Q 7985033
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T11:27:23+00:00 2026-06-04T11:27:23+00:00

This works SELECT DISTINCT b.b_id FROM b INNER JOIN c ON b.b_id=c.b_id WHERE c.active=’yes’

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This works

SELECT DISTINCT  b.b_id 
FROM             b INNER JOIN c 
ON               b.b_id=c.b_id  
WHERE            c.active='yes' AND b.featured='no'

When the results should be 0 rows returned, this returns a null row with count = 0

SELECT DISTINCT  b.b_id, COUNT(c.c_id) AS count
FROM             b INNER JOIN c 
ON               b.b_id=c.b_id  
WHERE            c.active='yes' AND b.featured='no'

Am I doing something wrong?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-04T11:27:25+00:00Added an answer on June 4, 2026 at 11:27 am

    I think you want a left join instead of an inner join since you want to return a count of 0 instead of a missing row when there is no matching c record for a given b record.

    Also, you should include a group by when using an aggregate function, such as count.

    SELECT
        b.b_id,
        COUNT(DISTINCT c.c_id) AS count
    FROM 
        b 
        LEFT JOIN c 
            ON b.b_id=c.b_id  
            AND c.active='yes' 
    WHERE b.featured='no'
    GROUP BY b.b_id
    
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