Question

Three tables

cats
=============
id
cat_herder_id
size
color
birthday

collars
=============
id
cat_id
diameter
color
material

cat_herders
=============
id
name
age
height

I want to get a row for each cat herder that is over a meter tall with a count of the number of cats that were born in February that are orange with black collars that belong to that herder and a count of all the cats that are orange with blue collars the belong to each herder, how would I go about doing a query of that sort.

I don’t think I can simply specify in the where statement because my count appears to be off, I am grouping by cat_herders.id

EDIT: Less sanitized, less abstracted version of what I have so far:

SELECT company.tblusers.first_name, company.tblusers.last_name, company.tblusers.userid, SUM(db.tasks.estimated_nonrecurring+db.tasks.estimated_recurring), COUNT(sugarcrm2.ncr_ncr.id),  
SUM(db.batch_log.time_elapsed) FROM company.tblusers 
INNER JOIN db.batch_log ON company.tblusers.userid = db.batch_log.userid 
INNER JOIN db.tasks ON db.batch_log.batch_id = db.tasks.batch_id
INNER JOIN sugarcrm2.ncr_ncr ON company.tblusers.first_name + " " + company.tblusers.first_name = sugarcrm2.ncr_ncr.employee
WHERE  departmentid = 8 AND DATE(db.batch_log.start_time) =  DATE(NOW()) GROUP BY userid

Answer 1

Note: Depending on your RDBMS and the datatype of the cats.birthday column, you’ll probably need to adjust this query to extract the birth month, but this gives you the general idea.

SELECT ch.name,
       SUM(CASE WHEN c.color = 'orange' AND cl.color = 'black' AND c.birthday = 'February' THEN 1 ELSE 0 END) AS OrangeCatsBlackCollarsFeb,
       SUM(CASE WHEN c.color = 'orange' AND cl.color = 'blue' THEN 1 ELSE 0 END) AS OrangeCatsBlueCollars 
    FROM cat_herders ch
        LEFT JOIN cats c
            INNER JOIN collars cl
                ON c.id = cl.cat_id
            ON ch.id = c.cat_herder_id
    WHERE ch.height > 1 /* in meters */
    GROUP BY ch.name