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Home/ Questions/Q 6734565
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T10:54:14+00:00 2026-05-26T10:54:14+00:00

To be direct here’s an example: ArrayList <?> x = new ArrayList(); ArrayList y

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To be direct here’s an example:

    ArrayList <?> x = new ArrayList();
    ArrayList y = new ArrayList();
    x.add("abc"); // Clause 1. Compilation error - No problemo. Understood.
    x.addAll(y); // Clause 2. No compilation error

For unbounded wildcard, one cannot add. Why there is no compilation error on the last statement?

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  1. Editorial Team
    Editorial Team
    2026-05-26T10:54:15+00:00Added an answer on May 26, 2026 at 10:54 am

    Because you are invoking the method with a raw type. The compiler can’t perform type checks. If you make y user generics, addAll(..) will fail.

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