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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T01:00:16+00:00 2026-05-12T01:00:16+00:00

to create an instance of another class from a class even if the class

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to create an instance of another class from a class even if the class I want to have an instance of is declared next of the class I am creating an instance from. Just like in C# and Java.

Thank you

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  1. Editorial Team
    Editorial Team
    2026-05-12T01:00:16+00:00Added an answer on May 12, 2026 at 1:00 am

    Sure. You just need a forward declaration. Something like this works just fine:

    #include <iostream>
    
    class B;
    
    class A {
    public:
        void hello( B &b );
        void meow();
    };
    
    class B {
    public:
        void hello( A &a );
        void woof();
    };
    
    void A::hello( B &b ) { b.woof(); }
    void A::meow() { std::cout << "Meow!" << std::endl; }
    
    void B::hello( A &a ) { a.meow(); }
    void B::woof() { std::cout << "Woof!" << std::endl; }
    
    int main() { A a; B b; a.hello( b ); b.hello( a ); return 0; }
    

    The key here is that you can only use pointers or references to a class until it has been fully defined. So in the example I gave, the hello() method in A can be declared to take a reference to B, even though we haven’t defined B at the point. After the definition of B, however, the definition of the method A::hello() is free to use B as it pleases.

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