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Home/ Questions/Q 8903131
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T01:47:30+00:00 2026-06-15T01:47:30+00:00

To find a module’s path, I would like to use the following script: import

  • 0

To find a module’s path, I would like to use the following script:

import <module_name>
print <module_name>.__file__

It works.

However, I want to make it more flexible, to receive an argument to specify the module’s name.

If I name the script as searchModulePath.py, I want to run it with searchModulePath.py <some_module_name>.

Here is what I have tried:

#!usr/bin/python

import sys
print sys.argv
import sys.argv[1]
print sys.argv[1].__file__

But it doesn’t work:

  File "searchModulePath.py", line 5
    import sys.argv[1]
                   ^
SyntaxError: invalid syntax

And, the print statement in the 2nd line doesn’t print out anything, 🙁

Anything I missed here?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-15T01:47:31+00:00Added an answer on June 15, 2026 at 1:47 am

    You can’t use variables in import statements, you should use the builtin __import__ in stead:

    import sys
    print sys.argv
    module = __import__(sys.argv[1])
    print module.__file__ 
    
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