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Home/ Questions/Q 8737815
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T10:36:24+00:00 2026-06-13T10:36:24+00:00

To get this code to compile: std::vector<Foo> factory() { std::vector<Foo> data; return data; }

  • 0

To get this code to compile:

std::vector<Foo> factory() 
{
    std::vector<Foo> data;
    return data;
}

I have to define my POD like this:

struct Foo
{
    const int i;
    const int j;

    Foo(const int _i, const int _j): i(_i), j(_j) {}

    Foo(Foo& foo): i(foo.i), j(foo.j){}

    Foo operator=(Foo& foo)
    {
        Foo f(foo.i, foo.j);
        return f;
    }
};

Is this the correct approach for defining a pod where I’m not interested in changing the pod members after creation? Why am I forced to define a copy constructor and overload the assignment operator? Is this compatible for different platform implementations of std::vector? Is it wrong in your opinion to have const PODS like this? Should I just leave them as non-const?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-13T10:36:25+00:00Added an answer on June 13, 2026 at 10:36 am

    It’s undefined behavior to create an std::vector over a type that you can’t assign. You can’t assign POD’s with const members.

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