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Home/ Questions/Q 864497
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T09:29:18+00:00 2026-05-15T09:29:18+00:00

To my surprise this code works fine: int i = 2; switch(i) { case

  • 0

To my surprise this code works fine:

int i = 2;
switch(i) {
case 1:
    String myString = "foo";
    break;
case 2:
    myString = "poo";
    System.out.println(myString);
}

But the String reference should never be declared? Could it be that all variables under every case always are declared no matter what, or how is this resolved?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T09:29:19+00:00Added an answer on May 15, 2026 at 9:29 am

    Well, it’s about brackets (i.e. scope).

    It’s better practice, arguably, to write your statements like so:

    int i = 2;
    switch(i) {
        case 1: {
            String myString = "foo";
            break;
        }
        case 2: {
            myString = "poo";
            System.out.println(myString);
        }
    }
    

    (I’m not near a Java compiler right now, but that shouldn’t compile).

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