Question

To select all children but a specific ID of a query, this would work:

$('.yourClass').children(':not(#idNotWanted)')

How would you select for additional not wanted IDs?

Here are some attempts thus far:

$('.yourClass').children(':not(#idNotWanted)' || ':not(#idNotWanted2)')
$('.yourClass').children(':not(#idNotWanted) || :not(#idNotWanted2)')
$('.yourClass').children(':not(#idNotWanted)' && ':not(#idNotWanted2)')
$('.yourClass').children(':not(#idNotWanted) && :not(#idNotWanted2)')`

Do the selector queries need to be assigned to an array, then remove the ID cases? or something else?

Answer 1

You could either do this:

$('.yourClass').children(':not(#idNotWanted):not(#idNotWanted2)')

Or, the better way, like this:

$('.yourClass').children(':not(#idNotWanted, #idNotWanted2)')

Separate your IDs with a comma inside your :not() selector. From the documentation;

All selectors are accepted inside :not(), for example: :not(div a) and :not(div,a).