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Home/ Questions/Q 6331101
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T17:59:41+00:00 2026-05-24T17:59:41+00:00

To start: <test style=font:2px;color:#FFFFFF bgcolor=#CCCCCC TOPMARGIN=5>style</test> Using XSLT/XPATH, I copy everything over from my

  • 0

To start:

<test style="font:2px;color:#FFFFFF" bgcolor="#CCCCCC" TOPMARGIN="5">style</test>

Using XSLT/XPATH, I copy everything over from my document

<xsl:template match="@* | node()">
  <xsl:copy>
    <xsl:apply-templates select="@* | node()"/>
  </xsl:copy>
</xsl:template>

But I’m not sure how to get this result using XSLT/XPATH:

<test style="background-color:#CCCCCC; margin-top:1;font:2px;color:#FFFFFF">style</test>

I think I’m failing at the XPATH. This is my attempt at just retrieving bgColor:

<xsl:template match="@bgColor">
 <xsl:attribute name="style">
   <xsl:text>background-color:</xsl:text>
   <xsl:value-of select="."/>
   <xsl:text>;</xsl:text>
   <xsl:value-of select="../@style"/>
 </xsl:attribute>
</xsl:template>

Unfortunately, even this breaks when style is placed after bgColor in the original document. How can I append these deprecated attribute values into one inline style attribute?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-24T17:59:41+00:00Added an answer on May 24, 2026 at 5:59 pm

    This transformation:

    <xsl:stylesheet version="1.0"
     xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
     <xsl:output omit-xml-declaration="yes" indent="yes"/>
    
     <xsl:template match="/*">
      <test style="{@style};background-color:{@bgcolor};margin-top:{@TOPMARGIN}">
       <xsl:value-of select="."/>
      </test>
     </xsl:template>
    </xsl:stylesheet>
    

    when applied on the provided XML document:

    <test style="font:2px;color:#FFFFFF"
          bgcolor="#CCCCCC" TOPMARGIN="5">style</test>
    

    produces the wanted, correct result:

    <test style="font:2px;color:#FFFFFF;background-color:#CCCCCC;margin-top:5">style</test>
    

    Explanation: Use of AVT.

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