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Home/ Questions/Q 8173053
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T21:59:41+00:00 2026-06-06T21:59:41+00:00

To string on a collection can get into a infinite loop if somewhere in

  • 0

To string on a collection can get into a infinite loop if somewhere in the graph of collected items is a reference back to itself. See example below.

Yes, good coding practices should prevent this in the first place, but anyway, my question is: What is the most efficient way to detect a recursion in this situation?

One approach is to use a set in a threadlocal, but that seems a bit heavy.

public class AntiRecusionList<E> extends ArrayList<E> {
  @Override
  public String toString() {
    if (  /* ???? test if "this" has been seen before */ ) {
        return "{skipping recursion}";
    } else {
        return super.toString();
    }
  }
}


public class AntiRecusionListTest {
  @Test
  public void testToString() throws Exception {
      AntiRecusionList<AntiRecusionList> list1 = new AntiRecusionList<>();
      AntiRecusionList<AntiRecusionList> list2 = new AntiRecusionList<>();
      list2.add(list1);
      list1.add(list2);
      list1.toString();  //BOOM !
  }
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-06T21:59:42+00:00Added an answer on June 6, 2026 at 9:59 pm

    The threadlocal bit I mentioned in the question:

    public class AntiRecusionList<E> extends ArrayList<E> {
    
    
    private final ThreadLocal<IdentityHashMap<AntiRecusionList<E>, ?>> fToStringChecker =
            new ThreadLocal<IdentityHashMap<AntiRecusionList<E>, ?>>() {
                @Override
                protected IdentityHashMap<AntiRecusionList<E>, ?> initialValue() {
                    return new IdentityHashMap<>();
                }
            };    
    
    @Override
    public String toString() {
        boolean entry = fToStringChecker.get().size() == 0;
        try {
            if (fToStringChecker.get().containsKey(this)/* test if "this" has been seen before */) {
                return "{skipping recursion}";
            } else {
                fToStringChecker.get().put(this, null);
                entry = true;
            }
            return super.toString();
        } finally {
            if (entry)
                fToStringChecker.get().clear();
        }
    }
    }
    
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