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Home/ Questions/Q 8427367
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T04:45:54+00:00 2026-06-10T04:45:54+00:00

To try string replace in Android, I wrote a small snippet: public class cs{

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To try string replace in Android, I wrote a small snippet:

public class cs{
 public static void main(String[] args){
   String a,c;
   int b;
   b=1;
   c="12345";
   a="12345,54321";
   a.replace(c,String.valueOf(b));
   System.out.println(a);
}
}

Expected Output: 12345,54321 changes to 1,54321

Actual Output: 12345,54321
。Please help。

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  1. Editorial Team
    Editorial Team
    2026-06-10T04:45:56+00:00Added an answer on June 10, 2026 at 4:45 am

    Is the . in c.String.valueOf(b) a typo for a comma, separating two parameters? Because it doesn’t make much sense as stated. replace accepts two parameters, and furthermore, it doesn’t change the string it’s executed on, it merely returns a new one, so you need to pick up that return value and reassign it to the variable:

    a = a.replace(c, String.valueOf(b));
    
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