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Home/ Questions/Q 6887077
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T05:50:24+00:00 2026-05-27T05:50:24+00:00

Today I found one interesting thing. I didn’t know that one can’t declare a

  • 0

Today I found one interesting thing. I didn’t know that one can’t declare a variable after a goto label.

Compiling the following code

#include <stdio.h>
int main() {
    int x = 5;
    goto JUMP;
    printf("x is : %d\n",x);
JUMP:
    int a = 0;  <=== giving me all sorts of error..
    printf("%d",a);
}

gives errors like

temp.c: In function ‘main’:
temp.c:7: error: expected expression before ‘int’
temp.c:8: error: ‘a’ undeclared (first use in this function)
temp.c:8: error: (Each undeclared identifier is reported only once
temp.c:8: error: for each function it appears in.)

Now what is the logic behind that? I heard that one cannot create variables inside the case statements of switch. Since JUMP is inside the same scope (the scope of main function, in my case) of the goto statement, I believe that scope is not an issue here. But then, why am I getting this error?

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  1. Editorial Team
    Editorial Team
    2026-05-27T05:50:25+00:00Added an answer on May 27, 2026 at 5:50 am

    The syntax simply doesn’t allow it. §6.8.1 Labeled Statements:

    labeled-statement:
        identifier : statement
        case constant-expression : statement
        default : statement
    

    Note that there is no clause that allows for a “labeled declaration”. It’s just not part of the language.

    You can trivially work around this, of course, with an empty statement.

    JUMP:;
    int a = 0;
    
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