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Home/ Questions/Q 7686707
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T19:32:26+00:00 2026-05-31T19:32:26+00:00

Today, I heard of Karatsuba algorithm, a fast multiplication algorithm. I am curious that

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Today, I heard of Karatsuba algorithm, a fast multiplication algorithm. I am curious that in which sense does this “fast” mean?

Normally, we consider a multiplication operation using * operator as O(1) when calculating the time complexity of a piece of code, and if it’s always true, how come we have a faster algorithm with regard to asymptotic notation? Or * should not be considered O(1) when performed on very large numbers, where Karatsuba algorithm can be useful?

And in the machine level, compilers always do some optimization on *. For example, using bit-wise operations to multiply a number by 2^n. Does Karatsuba algorithm beat * in the actual running time?

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  1. Editorial Team
    Editorial Team
    2026-05-31T19:32:28+00:00Added an answer on May 31, 2026 at 7:32 pm

    Classical multiplication is O(n2), where n is the number of digits in the number being multiplied.

    When measuring normal computer code, you’re dealing with fixed-size (typically 32-bit or 64-bit) numbers, so that becomes O(1) (since the size doesn’t change)

    Once you start dealing with BigIntegers, this becomes very important.

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