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Home/ Questions/Q 427697
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T19:36:07+00:00 2026-05-12T19:36:07+00:00

Today I wrote a small predicate to find matching symbols in a container. But

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Today I wrote a small predicate to find matching symbols in a container.

But I’m faced to a problem: I want to use this predicate in a std::find_if call inside a const-method of a class, searching in a container that is a member of this class.

But I just noticed that neither std::find nor std::find_if are able to operate on const_iterators !

I checked on some C++ references and it seems there is no version of std::find or std::find_if that accept/return const_iterators. I just can’t understand why, since from what I’ve seen, there is no way that these algorithms could modify the object referenced by the iterator.

Here is how is documented std::find in the SGI implementation:

Returns the first iterator i in the
range [first, last) such that *i ==
value. Returns last if no such
iterator exists.

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  1. Editorial Team
    Editorial Team
    2026-05-12T19:36:08+00:00Added an answer on May 12, 2026 at 7:36 pm

    std::find and std::find_if can definitely operate on *::const_iterator for a given container. Are you by chance looking at the signatures of those functions, and misunderstanding them?

    template <class InputIterator, class Type>
    InputIterator find(InputIterator first, InputIterator last, const Type& val);
    

    Note that InputIterator here is just a name of a template type parameter, and any const_iterator will satisfy the requirements for it.

    Or, perhaps, you’re confusing const_iterator (i.e. an iterator referencing a const value) with a const iterator (i.e. an iterator which is itself const)?

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