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Editorial Team
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Asked: 2026-06-13T19:14:21+00:00

Tough question to ask, but basically I have a web form with a title,

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Tough question to ask, but basically I have a web form with a “title”, “message” and “image” boxes, they all work in uploading it to one table on mysql.

What I want to do is have another field in my form for WHERE i want it to post to, I have 2 pages and 2 tables at the moment. table Blog and table Blog_2
They both work if I change my insert.php to INSERT INTO Blog or Blog_2

But i want to be able to use the field and a $_POST[Blog]
function which is linked to a field in a form, it’s going to have a dropdown box to select either Blog or Blog_2

Below is my code. I’ve given it a go, but I cant seem to make it work.
I created a variable called $insert as you can see.

Maybe its just a syntax problem, but im not that PHP savvy.

<?php
$con = mysql_connect("xxx","xxx","xxx");
mysql_select_db("databse") or die(mysql_error());

$insert = '$_POST[Blog]';

mysql_query("INSERT INTO $insert
(Date, Title, Message, Image) 
VALUES(now(), '$_POST[Title]' , '$_POST[Message]' , '$_POST[Image]' ) ")
or die(mysql_error()); 

echo "1 record added";


mysql_close($con);
?>
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1 Answer

  1. Editorial Team

    Try as below

    $insert = mysql_real_escape_string($_POST['Blog']);

mysql_query("INSERT INTO ".$insert."
(Date, Title, Message, Image) 
VALUES(now(), '$_POST[Title]' , '$_POST[Message]' , '$_POST[Image]' ) ")
or die(mysql_error());

    Recommendations:

    1.Learn to prevent from MySQL Injections: Good Link

    2.Mysql extension is not recommended for writing new code. Instead, either the mysqli or PDO_MySQL extension should be used. More reading: PHP Manual

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