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Home/ Questions/Q 6877993
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T04:40:07+00:00 2026-05-27T04:40:07+00:00

Tricky code: user = User.objects.filter(id=123) user[0].last_name = ‘foo’ user[0].save() # Cannot be saved. id(user[0])

  • 0

Tricky code:

user = User.objects.filter(id=123)
user[0].last_name = 'foo'
user[0].save()  # Cannot be saved.
id(user[0])     # 32131
id(user[0])     # 44232 ( different )

user cannot be saved in this way.

Normal code:

user = User.objects.filter(id=123)
if user:
  user[0].last_name = 'foo'
  user[0].save()  # Saved successfully.
  id(user[0])     # 32131
  id(user[0])     # 32131 ( same )

So, what is the problem?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T04:40:07+00:00Added an answer on May 27, 2026 at 4:40 am

    In first variant your user queryset isn’t evaluated yet. So every time you write user[0] ORM makes independent query to DB. In second variation queryset is evalutaed and acts like normal Python list.

    And BTW if you want just one row, use get:

    user = User.objects.get(id=123)
    
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