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Home/ Questions/Q 987085
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T05:25:25+00:00 2026-05-16T05:25:25+00:00

try: case_no = re.search(Case Number:</span></td><td><span class=\Value\>([^<]*?)<,br.response().read()).group(1) except: try: try: case_no = re.search(Citation Number:</span></td><td><span class=\Value\>([^<]*?)<,br.response().read()).group(1)

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try:
    case_no  = re.search("Case Number:</span></td><td><span class=\"Value\">([^<]*?)<",br.response().read()).group(1)
except:
       try:
           try:
               case_no  = re.search("Citation Number:</span></td><td><span class=\"Value\">([^<]*?)<",br.response().read()).group(1)
            except:
               case_no  = re.search("Citation Number:</span></td><td><span class=\"Value\">([^<]*?)<",br.response().read()).group(1)
        except:
              case_no  = "N/A"

As you can see the above code is quite clumsy. I want to know if there is any way I can do like this.

try:
    XYZ
except:
    DOXYZ
except:
    DOXYZ

Basically I want to be able to use – “try X if exception then try Y if exception then try Z” without nesting too much statemtns.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T05:25:26+00:00Added an answer on May 16, 2026 at 5:25 am

    Probably you shouldn’t be checking exception at all?

    patterns = [
      "Case Number:</span></td><td><span class=\"Value\">([^<]*?)<",
      "Citation Number:</span></td><td><span class=\"Value\">([^<]*?)<",
      "Citation Number:</span></td><td><span class=\"Value\">([^<]*?)<"   # same as #2?
    ]
    text = br.response().read()
    case_no  = "N/A"
    for pattern in patterns:
      res = re.search(pattern, text)
      if res:
        case_no = res.group(1)
        break
    
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