Question

try:
    num = int(input("Give me an integer between 1 and 100:"))
    while num > 100 or num < 1:
        print ("Sorry, that is not an integer between 1 and 100. Try again.")
        num = int(input("Give me an integer between 1 and 100:"))
except:
    print ("Sorry, that is not an integer between 1 and 100. Try again.")
else:
    print ("Thank you for your input")

How do I tell Python to also print “sorry try again” if they entered input such as “pear” or “sd23214”? Thank you.

Answer 1

Just wrap it all in a while loop

while True:
    try:
        num = int(input("Give me an integer between 1 and 100:"))
        if num > 100 or num < 1:
            print ("Sorry, that is not an integer between 1 and 100. Try again.")
            continue
    except ValueError:
        print ("Sorry, that is not an integer between 1 and 100. Try again.")
    else:
        print ("Thank you for your input")
        break

Most people would probably not use the else clause here

while True:
    try:
        num = int(input("Give me an integer between 1 and 100:"))
        if num > 100 or num < 1:
            raise ValueError
        print ("Thank you for your input")
        break
    except ValueError:
        print ("Sorry, that is not an integer between 1 and 100. Try again.")