Question

Trying this answer and not having any luck:

I am using the SQLite Database browser (built with 3.3.5 of the SQLite engine) to execute this query:

SELECT columnX FROM MyTable

WHERE columnX LIKE  '%\%16'  ESCAPE '\'  

In column XI have a row with the data: sampledata%167

I execute the statement and get no data returned but no error either?

http://www.sqlite.org/lang_expr.html

(SQLite with C API)

Answer 1

I think the problem is that you are missing a % from the end of the pattern.

'%\%16%'

Also backslashes often cause confusion in various programming languages and tools, especially if there is multiple levels of parsing involved before the query gets to the database. To simplify things you could try a different escape character instead:

WHERE columnX LIKE '%!%16%' ESCAPE '!'