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Home/ Questions/Q 390291
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T15:57:01+00:00 2026-05-12T15:57:01+00:00

Trying to copy a char *str to char c[] but getting segmentation fault or

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Trying to copy a char *str to char c[] but getting segmentation fault or invalid initializer error.

Why is this code is giving me a seg fault?

char *token = "some random string";
char c[80];  
strcpy( c, token);
strncpy(c, token, sizeof c - 1); 
c[79] = '\0';
char *broken = strtok(c, "#");
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  1. Editorial Team
    Editorial Team
    2026-05-12T15:57:01+00:00Added an answer on May 12, 2026 at 3:57 pm

    use strncpy() rather than strcpy()

    /* code not tested */
    #include <string.h>
    
    int main(void) {
      char *src = "gkjsdh fkdshfkjsdhfksdjghf ewi7tr weigrfdhf gsdjfsd jfgsdjf gsdjfgwe";
      char dst[10]; /* not enough for all of src */
    
      strcpy(dst, src); /* BANG!!! */
      strncpy(dst, src, sizeof dst - 1); /* OK ... but `dst` needs to be NUL terminated */
          dst[9] = '\0';
      return 0;
    }
    
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