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Home/ Questions/Q 8030375
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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T00:44:52+00:00 2026-06-05T00:44:52+00:00

Trying to create a list of files with multiple extensions over which to iterate.

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Trying to create a list of files with multiple extensions over which to iterate. Most of the answers on stack overflow involve filtering using lambda but I’m not sure how this can work in this case (just because of the way the iteration would be set up). So far I have

import fnmatch

excluded = ['*.py', '*.py~']

fileNames = []

for fileName in os.listdir('.'):
    fileNames.append(fileName)
    print fileNames

for p in excluded:
    if fnmatch.fnmatch(fileName, p):
        fileNames.remove(fileName)
        print fileNames

Obviously the problem is that list.remove only removes the first instance and not all instances. What do you reckon would be the most efficient way to solve this problem?

Thanks!

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  1. Editorial Team
    Editorial Team
    2026-06-05T00:44:53+00:00Added an answer on June 5, 2026 at 12:44 am

    Use a list comprehension )):

    filtered = [x for x in os.listdir('.') if not any(fnmatch.fnmatch(x, p) for p in excluded)]
    

    Alternatively, a more compact code using regular expressions:

    filtered = [x for x in os.listdir('.') if not re.search(r'\.py~?$', x)]
    

    or simply use endswith

    excluded = ('.py', '.py~')
    filtered = [x for x in os.listdir('.') if not x.endswith(excluded)]
    
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