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Home/ Questions/Q 7822375
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Editorial Team
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Editorial Team
Asked: June 2, 20262026-06-02T07:54:38+00:00 2026-06-02T07:54:38+00:00

Trying to create a random array to be sorted by all the standard sorting

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Trying to create a random array to be sorted by all the standard sorting algorithms.

I can’t remember how i solved this before, had a recent computer crash and lost my work. i know i have to some how wrap an int array using casting but can’t remember exactly how.

package project6;
import java.util.*;

public class RandomArray
{
Random r;

Integer[] arr100 = new Integer[100];

Integer[] arr1000 = new Integer[1000];

Integer[] arr500K = new Integer[500000];

Integer[] arr1M = new Integer[1000000];

public RandomArray()
{
    r = new Random();
}

public Integer[] test100()
{
    for( int i=0; i<arr100.length; i++ )
    {
        r.nextInt( arr100[i] );
    }
    return arr100;
}

public Integer[] test1000()
{
    for( int i=0; i<arr1000.length; i++ )
    {
        r.nextInt( arr1000[i] );
    }
    return arr1000;
}

public Integer[] test500K()
{
    for( int i=0; i<arr500K.length; i++ )
    {
        r.nextInt( arr500K[i] );
    }
    return arr500K;
}

public Integer[] test1M()
{
    for( int i=0; i<arr1M.length; i++ )
    {
        r.nextInt( arr1M[i] );
    }
    return arr1M;
}

}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-02T07:54:40+00:00Added an answer on June 2, 2026 at 7:54 am

    I think you have your assignment backwards. Looks like you want to fill up the array with integers so:

     arr1M[i] = r.nextInt();
    

    With the code you have now you are passing a null value to the r.nextInt(int N) function because the arrays are not populated yet.

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