Question

Trying to figure out how to use the Jquery .on() method with a specific selector that has multiple events associated with it. I was previously using the .live() method, but not quite sure how to accomplish the same feat with .on(). Please see my code below:

$("table.planning_grid td").live({
  mouseenter:function(){
     $(this).parent("tr").find("a.delete").show();
  },
  mouseleave:function(){
     $(this).parent("tr").find("a.delete").hide();        
  },
  click:function(){
    //do something else.
  }
});
       

I know I can assign the multiple events by calling:

 $("table.planning_grid td").on({
    mouseenter:function(){  //see above
    },
    mouseleave:function(){ //see above
    }
    click:function(){ //etc
    }
  });

But I believe the proper use of .on() would be like so:

   $("table.planning_grid").on('mouseenter','td',function(){});

Is there a way to accomplish this? Or what is the best practice here? I tried the code below, but no dice.

$("table.planning_grid").on('td',{
   mouseenter: function(){ /* event1 */ }, 
   mouseleave: function(){ /* event2 */ },
   click: function(){  /* event3 */ }
 });

Answer 1

That’s the other way around. You should write:

$("table.planning_grid").on({
    mouseenter: function() {
        // Handle mouseenter...
    },
    mouseleave: function() {
        // Handle mouseleave...
    },
    click: function() {
        // Handle click...
    }
}, "td");