Question

Trying to figure out this pseudo code. The following is assumed….
I can only use unsigned and signed integers (or long).
Division returns a real number with no remainder.
MOD returns a real number.
Fractions and decimals are not handled.

INT I = 41828;
INT C = 15;
INT D = 0;

D = (I / 65535) * C;

How would you handle a fraction (or decimal value) in this situation? Is there a way to use negative value to represent the remainder?

In this example I/65535 should be 0.638, however, with the limitations, I get 0 with a MOD of 638. How can I then multiply by C to get the correct answer?

Hope that makes sense.

MOD here would actually return 23707, not 638. (I hope I’m right on that 🙂 )

Answer 1

If you were to switch your order of operations on that last line, you would get the integer answer you’re looking for (9, if my calculations are correct)

D = (I * C) / 65535
/* D == 9 */

Is that the answer you’re looking for?