Question

Trying to find a more elegant way to create an int that has discrete levels. My example only shows 6 different levels but I am wanting to do this for 45 different levels, so don’t want 45 if elses. Not sure what this is called in math and so can’t seem to find what I am looking for.

sd = some double value

int level = 0;

if (Double.compare(sd, 0.41) >= 0) {
    level = 5;
} else if(Double.compare(sd, 0.25) >= 0) {
    level = 4;
} else if(Double.compare(sd, 0.11) >= 0) {
    level = 3;
} else if(Double.compare(sd, 0.05) >= 0) {
    level = 2;
} else if(Double.compare(sd, 0.02) >= 0) {
    level = 1;
}

…………….

Latest Update FYI these were the values I needed to quantize:
As you can see I needed something a little more elegant, Used Navigable Map answer

public static final int[] Levels = { 
        3100, 3250, 3383, 3517, 3650, 
        3673, 3695, 3718, 3740, 3760, 
        3780, 3800, 3820, 3853, 3885,
        3918, 3950, 3975, 4000, 4025, 4050
        };

Answer 1

http://download.oracle.com/javase/6/docs/api/java/util/NavigableMap.html

NavigableMap<Integer, Integer> map = new TreeMap<Integer, Integer>();
map.put(0, 0);    // 0..4     => 0
map.put(5, 1);    // 5..10    => 1
map.put(10, 2);   // 10..100  => 2
......

You can implement it with Double data type too.