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Home/ Questions/Q 7738133
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T08:11:08+00:00 2026-06-01T08:11:08+00:00

Trying to make manageable output for Android to convert $output into JSONObjects. When I

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Trying to make manageable output for Android to convert $output into JSONObjects. When I use the commented out bottom line, it receives the data in Android’s log just fine, but can’t convert JSONArray to JSONObject – thus the desire for a foreach loop to return each SQL row on its own. I can’t see any syntax issues, so I don’t know what PHP is complaining about – any ideas? Also, when I use the commented out print code, it returns proper results, so I know it’s no problem accessing the db.
Here’s the code:

<?php

define("DB_HOST", "localhost");
define("DB_USER", "*");
define("DB_PASSWORD", "*");
define("DB_DATABASE", "*");

mysql_connect(DB_HOST, DB_USER, DB_PASSWORD);
mysql_select_db(DB_DATABASE);
$sql=mysql_query("select * from QUESTIONS where CATEGORY like 'elections'");
while($row=mysql_fetch_assoc($sql))
$output[]=$row;
foreach($output) {
echo $output;
}
mysql_close();


//print(json_encode($output));
?>

And here’s the error:

Parse error: syntax error, unexpected ')' in /home/frehud/public_html/android_api/getQuestions/index.php on line 13
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-01T08:11:10+00:00Added an answer on June 1, 2026 at 8:11 am

    you need to use as keyword and assign each value in a variable ($value here).Then echo that variable.

    like below :

    foreach($output as $value) {
    echo $value;
    }
    
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