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Home/ Questions/Q 7672141
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T16:13:04+00:00 2026-05-31T16:13:04+00:00

Trying to pass something to something else. Says undefined. Not sure how or why.

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Trying to pass something to something else. Says undefined. Not sure how or why.

clsapp.on 'mysqld', ->
  getHostById = (host) -> cls.getHostById.acq host, (c) -> JSON.stringify(result)

I need some way to access getHostById('localhost').hostname while inside another part of the .js

clsapp.on getHostById('localhost'), (c) ->   
  console.log JSON.parse(getHostById('localhost')).hostname

is just null or undefined

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  1. Editorial Team
    Editorial Team
    2026-05-31T16:13:05+00:00Added an answer on May 31, 2026 at 4:13 pm

    It’s hard to understand what you’re asking, but I’ll make some observations:

    In the code

    clsapp.on 'mysqld', ->
      getHostById = (host) -> cls.getHostById.acq host, (c) -> JSON.stringify(result)
    

    you probably meant for the callback argument to be called result, not c. Unless you’re defining result elsewhere.

    More importantly, there has got to be a clearer way for you to write this code. Just expanding the definition of getHostById to be multi-line helps a bit:

    clsapp.on 'mysqld', ->
      getHostById = (host) ->
        cls.getHostById.acq host, (result) -> JSON.stringify(result)
    

    Now, I think that ultimately, your problem is that you’re trying to make an async function behave synchronously—which you can’t do in JavaScript (or CoffeeScript, which is a thin syntactic layer on top of JS). Since cls.getHostById.acq takes a callback, it’s almost certainly designed to call that callback after it returns so that it doesn’t block the thread. Which means that there’s no way for you to write a getHostById function that simply returns a value, as your JSON.parse(getHostById('localhost')) example suggests. You’ll have to use a callback.

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