Question

Trying to set up some basic socket code in Python (well, Jython, but I don’t think that’s relevant here).

import socket
class Foo(object):
    def __init__(self):
        #some other init code here

        s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
        s.connect("localhost", 2057)
        s.send("Testing 1,2,3...")
        data = s.recv()
        s.close()
        print data

It tells me:

    s.connect("localhost", 2057)
  File "<string>", line 1, in connect
TypeError: connect() takes exactly 2 arguments (3 given)

I get the feeling something really simple is staring me in the face, but I can’t tell what I’m doing wrong.

Answer 1

You have to pass a Tuple to connect() method.

s.connect( ('localhost', 2057) )

The first (implicit) argument expected is self, the second is the Tuple.