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Home/ Questions/Q 6754099
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T13:14:25+00:00 2026-05-26T13:14:25+00:00

Trying to use exportDoc.Root.Elements(string).Where(node => !(node.Element(product).HasElements) || node.Element(product).Element(type).Value != product).Remove(); to remove the nodes

  • 0

Trying to use

exportDoc.Root.Elements("string").Where(node => !(node.Element("product").HasElements) || node.Element("product").Element("type").Value != product).Remove();

to remove the nodes in my XML document where the product string I’m searching for doesn’t occur. Here is a sample of my XML structure:

<root>
   <string id = "Hithere">
      <product>
         <type>orange</type>
         <type>yellow</type>
         <type>green</type>
      <product>
      <element2/>
      <element3/>
    </string>
    <string id ="...">
     ...
     ... 
</root>

So I need to look under the product element of each string element AND at each of the type elements therein to see if the value of string product (input to the method where this is contained) occurs. At present, it looks like my code only removes the node if the product string I’m searching for matches the value of just the first type element.

The whole point is to remove all string nodes from this xdoc that don’t have the product I’m looking for listed under their product element.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T13:14:25+00:00Added an answer on May 26, 2026 at 1:14 pm

    You need to change your search condition slightly:

    var nodesToRemove = xDoc.Root
        .Elements("string")
        .Where(node =>
            !(node.Element("product").HasElements) ||
            node.Element("product").Elements("type").All(x => x.Value != product))
        .ToList();
    

    This should match elements which all string:product:types differ from product value (or in other words – if at least one <type> will match your product, it won’t be marked for removal).

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