Question

two py file:

./src/foo.py

def bar ():
    print 'bar!'

./tests/testfoo.py

from foo import bar
print 'testing'
bar ()

in the root folder ‘./’, calling

python ./tests/testfoo.py

the result is

Traceback (most recent call last):
  File "./tests/testfoo.py", line 1, in <module>
    from foo import bar
ImportError: No module named foo

running the testfoo.py but naturally module foo could not be found by the interpreter. can i give any parameter to interpreter to lookup modules in the folder ‘src’?

Edit #1

also added two empty init.py file.

./src/__init__.py
./tests/__init__.py

still getting the same error.

Edit #2 (Solution)

I solved problem by adding a new initialization py file

prep.py

import os, sys
cur = os.path.dirname (__file__)
pathtest = os.path.join (cur, 'tests')
sys.path.append (pathtest)

then called:

python prep.py tests/testfoo.py

it worked

Answer 1

Try this:

import sys
sys.path.append('your/path')
import testfoo

You may need to make ./tests an absolute path…