Home/ Questions/Q 258051
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Asked: 2026-05-11T22:08:54+00:00

Typically the default implementation of Object.hashCode() is some function of the allocated address of

  • 0

Typically the default implementation of Object.hashCode() is some function of the allocated address of the object in memory (though this is not mandated by the Java Language Specification). Given that the VM shunts objects about in memory, why does the value returned by System.identityHashCode() never change during the object’s lifetime?

If it is a "one-shot" calculation (the object’s hashCode is calculated once and stashed in the object header or something), then does that mean it is possible for two objects to have the same identityHashCode (if they happen to be first allocated at the same address in memory)?

Share

Leave an answer

You must login to add an answer.

Need An Account,

1 Answer

  1. Editorial Team

    Modern JVMs save the value in the object header. I believe the value is typically calculated only on first use in order to keep time spent in object allocation to a minimum (sometimes down to as low as a dozen cycles). The common Sun JVM can be compiled so that the identity hash code is always 1 for all objects.

    Multiple objects can have the same identity hash code. That is the nature of hash codes.

    • 0