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Home/ Questions/Q 5967683
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T19:58:46+00:00 2026-05-22T19:58:46+00:00

umask(0); fd = open(/dev/null, O_RDWR); Here’s man 2 umask : umask() sets the calling

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umask(0);

fd = open("/dev/null", O_RDWR);

Here’s man 2 umask:

umask() sets the calling process’s file mode creation mask (umask) to mask & 0777.

But it doesn’t make sense for me,as when we call open ,we will also provide a mode parameter.

So what’s the point of umask?

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  1. Editorial Team
    Editorial Team
    2026-05-22T19:58:47+00:00Added an answer on May 22, 2026 at 7:58 pm

    The umask is applied to all modes used in file system operations. From the manual open(2):

    The permissions of the created file are (mode & ~umask)

    So with a single call to umask, you can influence the mode of all create files.

    This is usually used when a program wants the user to allow to overrule the default grants for files/directories it creates. A paranoid user (or root) can set the umask to 0077 which means that even if you specify 0777 in open(2), only the current user will have access.

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