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Home/ Questions/Q 9178141
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T17:28:59+00:00 2026-06-17T17:28:59+00:00

Under OS X, I have a bash shell script which takes a parameter (which

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Under OS X, I have a bash shell script which takes a parameter (which is a folder name)

when I call:

echo "Build Starting for $1" | tee ~/MyFolder/$1/build.log

It works right. It echos the right “$1” parameter into the ~/MyFolder/$1/build.log file (which exist). However, when I call another executable and trying to make use of the $1 parameter, the parameter is always empty.

xcodebuild -configuration Release -project MyProject.xcodeproj | tee -a ~/MyFolder/$1/build.log

this creates “build.log” in “~/MyFolder” and the $1 is ignored.

Why is that? Do I need to “export” it somehow?

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  1. Editorial Team
    Editorial Team
    2026-06-17T17:29:00+00:00Added an answer on June 17, 2026 at 5:29 pm

    If you’re calling a function or another script and want the same $1, $2,.. to be available, use:

    myFunctionOrScript "$@"
    

    "$@" is equivalent to "$1" "$2" "$3" ..., and will thus make sure “$1” in the subprocess is the same as “$1” in the parent process.

    You can also assign their values to new, named variables:

    export mydir=$1
    

    and then use $mydir in place of $1 in subprocess scripts.

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