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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T18:12:38+00:00 2026-05-13T18:12:38+00:00

Unfortunately I cannot provide any code examples, however I will try and create an

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Unfortunately I cannot provide any code examples, however I will try and create an example.
My question is about Objects and memory allocation in PHP.

If I have an object, lets say:

$object = new Class();

Then I do something like

$object2 = $object;

What is this actualy doing? I know there is a clone function, but thats not what I’m asking about, I’m concerned about whether this is creating another identical object, or if its just assigning a reference to $object.

I strongly understand this to mean that it just creates a reference, but in some case usages of mine, I find that I get another $object created, and I can’t understand why.

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  1. Editorial Team
    Editorial Team
    2026-05-13T18:12:38+00:00Added an answer on May 13, 2026 at 6:12 pm

    If you use the magic method __invoke, you can call an object similar to a function, and it will call that magic method.

    class Object{
        function __invoke(){ return "hi"; }
    }
    
    $object = new Object;
    $object2 = $object();
    echo $object2; // echos hi
    

    That means that $object2 is equal to whatever that function returns.

    Basically, you are calling a function, but using a variable as it’s name. So:

    function test(){ echo "hi"; }
    $function_name = "test";
    $function_name(); // echos hi.
    

    In this case, you are just calling an object instead.

    So, in reference to your question, this is actually not ‘cloning’ at all, unless the __invoke() function looks like this:

    function __invoke(){ return this }
    

    In which case, it would be a reference to the same class.

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