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Home/ Questions/Q 797903
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T22:53:02+00:00 2026-05-14T22:53:02+00:00

union { int i; bool b; } x; x.i = 20000; x.b = true;

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union
{ int i;
  bool b;
} x;

x.i = 20000;
x.b = true;
cout << x.i;

It prints out 19969. Why does it not print out 20000?

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  1. Editorial Team
    Editorial Team
    2026-05-14T22:53:03+00:00Added an answer on May 14, 2026 at 10:53 pm

    A union is not a struct. In a union, all of the data occupies the same space and can be treated as different types via its field names. When you assign true to x.b, you are overwriting the lower-order bits of 20000.

    More specifically:

    20000 in binary: 100111000100000

    19969 in binary: 100111000000001

    What happened here was that you put a one-byte value of 1 (00000001) in the 8 lower-order bits of 200000.

    If you use a struct instead of a union, you will have space for both an int and a bool, rather than just an int, and you will see the results you expected.

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