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Home/ Questions/Q 731355
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T07:01:02+00:00 2026-05-14T07:01:02+00:00

Up until now I just put all my jQuery goodness inside the $(document).ready() function,

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Up until now I just put all my jQuery goodness inside the $(document).ready() function, including simple functions used in certain user interactions.

But functions that don´t require the DOM document to be loaded or are only called afterwards anyway, can be placed outside the $(document).ready() as well. Consider for example a very simple validation function such as:

function hexvalidate(color) {
// Validates 3-digit or 6-digit hex color codes 
 var reg = /^(#)?([0-9a-fA-F]{3})([0-9a-fA-F]{3})?$/;
 return reg.test(color);
}

The function is only called from within the $(document).ready() function though.

What is best practice (syntax, speed); placing such a function inside or outside the jquery document ready function?

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  1. Editorial Team
    Editorial Team
    2026-05-14T07:01:02+00:00Added an answer on May 14, 2026 at 7:01 am

    Put it inside so it won’t pollute the global namespace. It also ensures a faster resolve of the function name because of JavaScript’s scope chains.

    Put it outside if it’s a reusable component so you could easily move it in a separate file and call from different contexts.

    Since you already use JQuery, it’s worth mentioning, that in your case you may want to define hexvalidate as a JQuery plugin outside and then invoke it inside.

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