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Editorial Team
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Asked: 2026-05-23T18:05:56+00:00

UPDATE 1: I can get around the problem with a try/catch, but I would

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UPDATE 1:

I can get around the problem with a try/catch, but I would prefer not to use this method when I know what the problem is:

try {
    buildHTML.push( "<tr><td>" + day.td[0].div.abbr.content + "</td><td><img src='" + day.td[1].div.div.img.src + "' /></td><td>" + day.td[2].span[0].span.content + "</td><td>" + day.td[3].span[0].span.content + "</td><td>" + day.td[4].span[0].span[1].content + "</td>");
} catch(err) {
    buildHTML.push( "<tr><td>" + day.td[0].div.abbr.content + "</td><td><img src='" + day.td[1].div.div.img.src + "' /></td><td></td><td>" + day.td[3].span[0].span.content + "</td><td>" + day.td[4].span[0].span[1].content + "</td>");
}

ORIGINAL QUESTION:

Using the following jsonp service:

http://query.yahooapis.com/v1/public/yql?q=select%20*%20from%20html%20where%20url%20%3D%20%22http%3A%2F%2Fnews.bbc.co.uk%2Fweather%2Fforecast%2F4276%3F%26search%3Dgerrards%2520cross%26itemsPerPage%3D10%26region%3Dworld%26area%3DGerrards%2520Cross%22%20and%20xpath%3D’%2F%2Ftbody’&format=json&callback=cbfunc22

I use the following script to capture the data:

$(document).ready(function() {
    get_bbc_weather();

    function get_bbc_weather() {
        $.ajax({
            url: "http://query.yahooapis.com/v1/public/yql?q=select%20*%20from%20html%20where%20url%20%3D%20%22http%3A%2F%2Fnews.bbc.co.uk%2Fweather%2Fforecast%2F4276%3F%26search%3Dgerrards%2520cross%26itemsPerPage%3D10%26region%3Dworld%26area%3DGerrards%2520Cross%22%20and%20xpath%3D'%2F%2Ftbody'&format=json&callback=cbfunc22&rand=" + Math.random(),
            type: 'GET',
            dataType: 'jsonp',
            jsonp: 'callback',
            jsonpCallback: 'cbfunc22',
            error: function(xhr, status, error) {
                alert(xhr.responseText);
            },
            success: function(data) { 
                var buildHTML = [];

                var weather = data.query.results.tbody.tr;

                buildHTML.push("<tr><td>Day</td><td>Weather</td><td>Max<br />Day<br />(°C)</td><td>Min<br />Night<br />(°C)</td><td>Wind<br />(MPH)</td>");

                for (var i = 0; i < weather.length; i++) {
                    var day = weather[i];

                    buildHTML.push( "<tr><td>" + day.td[0].div.abbr.content + "</td><td><img src='" + day.td[1].div.div.img.src + "' /></td><td>" + day.td[2].span[0].span.content + "</td><td>" + day.td[3].span[0].span.content + "</td><td>" + day.td[4].span[0].span[1].content + "</td>");
                }

                $('#divContent1').empty().append("<table>" + buildHTML.join("</tr>") + "</table>")


            }
        });

    }

});

However, at a certain time of the day, day.td[2].span[0].span.content becomes null. When this happens, how do I detect it and use the next temp min section instead only for the first day? The rest of the days should continue to use the temp max section.

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1 Answer

  1. Editorial Team

    I may be stating the obvious here, but why not just use an if statement? 

    if (day.td[2].span[0].span.content != null) {
    buildHTML.push( "<tr><td>" + day.td[0].div.abbr.content + "</td><td><img src='" + day.td[1].div.div.img.src + "' /></td><td>" + day.td[2].span[0].span.content + "</td><td>" + day.td[3].span[0].span.content + "</td><td>" + day.td[4].span[0].span[1].content + "</td>");
} 
else {
    buildHTML.push( "<tr><td>" + day.td[0].div.abbr.content + "</td><td><img src='" + day.td[1].div.div.img.src + "' /></td><td></td><td>" + day.td[3].span[0].span.content + "</td><td>" + day.td[4].span[0].span[1].content + "</td>");
}
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