Question

UPDATE: Here’s my solution (inspired by accepted answer):

function log(msg, values) {
         if(config.log == true){
         msg = [msg];
         var args = msg.concat(values);
         console.log.apply( this, args );
         }
     }

UPDATE2: Even better solution:

 function log(msg) {
     if(config.log == true){
     msg = [msg];
     var values = Array.prototype.slice.call(arguments, 1);
     var args = msg.concat(values);
     console.log.apply( console, args );
     }
 }

You can call this version like so:

log("Hi my name is %s, and I like %s", "Dave", "Javascript");

Here’s the original question:

console.log takes a string and replaces tokens with values, for example:

console.log("My name is %s, and I like %", 'Dave', 'Javascript')

would print:

My name is Dave, and I like Javascript

I’d like to wrap this inside a method like so:

function log(msg, values) {
  if(config.log == true){
    console.log(msg, values);
   }
 }

The ‘values’ arg might be a single value or several optional args. How can I accomplish this?

If I call it like so:

 log("My name is %s, and I like %s", "Dave", "Javascript");

I get this (it doesn’t recognize “Javascript” as a 3rd argument):

 My name is Dave, and I like %s

If I call this:

 log("My name is %s, and I like %s", ["Dave", "Javascript"]);

then it treats the second arg as an array (it doesn’t expand to multiple args). What trick am I missing to get it to expand the optional args?

Answer 1

Though this isn’t jQuery related, I can try answer it anyway 🙂

Following might work (untested):

function log(msg, values) {
  if(typeof config.log != 'undefined' ) {
    if( typeof values != 'Array' ) {
      values = [values];
    }
    values.unshift( msg );
    console.log.apply( this, values );
  }
}