Question

UPDATE

I have got a log file of 1000 lines containing some reference.

Time Reference Date of start Date of end
12:00 AT001 13 November 2011 15 November 2011
13:00 AT038 15 December 2012 17 December 2012
14:00 AT076 17 January 2013 19 January 2013

$ref1 = AT038

Basically, I want to parse the log file and have an output (line by line) for $ref1 such as :

Time : 13h
Reference : AT038
Date of start : 15 December 2012
Date of end : 17 December 2012

Thanks in advance

Answer 1

try:

$ref1 = "AT038"
$csv = Import-Csv .\myfile.txt -Delimiter ' '#Import file as CSV with space as delimiter
$csv | ? { $_.reference -EQ $ref1 } | FL #Piping each line of CSV to where-object cmdlet,  filtering only line where value of column reference is equal to $ref1 variable value. Piping the result of the filtering to file-list to have output as requested in OP.

Code added after requisite are changed in OP:

$ref1 = "AT038"
$txt = gc .\myfile.txt
$txt2 = $txt | % { $b = $_ -split ' '; "$($b[0]) $($b[1]) $($b[2])_$($b[3])_$($b[4]) $($b[5])_$($b[6])_$($b[7])" }
$csv = convertfrom-csv -InputObject $txt2 -Delimiter ' ' 
$csv | ? { $_.reference -EQ $ref1 } | FL