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Home/ Questions/Q 1081187
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T22:08:14+00:00 2026-05-16T22:08:14+00:00

**Update: Title should have read: Sql Query – Unique item with latest entry Hi

  • 0

**Update: Title should have read: Sql Query – Unique item with latest entry

Hi there,

I have a two tables. users and rsvp.
Users has user detail in it (id, name, email)
rsvp has rsvp status in it (answerid, userid, eventid, answer)

Note:
answer 1 = coming
answer 2 = not coming
answer 3 = maybe
answer 4 (pseudo answer) = no reply

Please note that “answer 4” never ever appears in the actual rsvp table data.
It is constructed on the fly with the below SQL

A query to see whos coming, whos not, whos maybe coming AND who has not responded looks as follows:

 SELECT
  usrs.name,
  usrs.email,

  (SELECT CASE 
  WHEN rsvp.answer = 1 THEN 'Yes, see you there' 
  WHEN rsvp.answer = 2 THEN 'Cannot make it' 
  WHEN rsvp.answer = 4 THEN 'Cannot make it' 
  WHEN rsvp.answer = 3 THEN 'Maybe'
  ELSE 'No Reply' END) as attendance,

  (SELECT CASE 
  WHEN rsvp.answer = 1 THEN "1" 
  WHEN rsvp.answer = 2 THEN "3"
  WHEN rsvp.answer = 4 THEN "4"
  WHEN rsvp.answer = 3 THEN "2"
  ELSE "5" END) as ordering

  FROM jos_users usrs
  LEFT JOIN jos_rsvp as rsvp on usrs.id = rsvp.userid
  WHERE usrs.id NOT IN (62,63,128)
  ORDER BY ordering

The same user may reply more than once. I.e. First they reply YES and then later they change their mind and reply NO.

rsvp answers are not updated, a new record is simply inserted for the new answer.
The problem with the SQL above is that it does not take this duplication into account.

I’m trying to figure out how to change it so that only the last answer for each user is shown in the results. It seemed simple at first, but now I cant figure it out.

Using MySQL.

Please Help,
Losing Hair
n4~

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T22:08:14+00:00Added an answer on May 16, 2026 at 10:08 pm

    How about this?

     SELECT
      usrs.name,
      usrs.email,
    
      (SELECT CASE 
      WHEN rsvp.answer = 1 THEN 'Yes, see you there' 
      WHEN rsvp.answer = 2 THEN 'Cannot make it' 
      WHEN rsvp.answer = 4 THEN 'Cannot make it' 
      WHEN rsvp.answer = 3 THEN 'Maybe'
      ELSE 'No Reply' END) as attendance,
    
      (SELECT CASE 
      WHEN rsvp.answer = 1 THEN "1" 
      WHEN rsvp.answer = 2 THEN "3"
      WHEN rsvp.answer = 4 THEN "4"
      WHEN rsvp.answer = 3 THEN "2"
      ELSE "5" END) as ordering
    
      FROM jos_users usrs, jos_rsvp rsvp,
      (SELECT userid, max(answerid) AS latest_answerid
       FROM jos_rsvp
       WHERE userid NOT IN (62,63,128)
       GROUP BY userid
      ) AS latest_rsvp
      WHERE usrs.id = rsvp.userid
      AND rsvp.userid = latest_rsvp.userid
      AND rsvp.answerid = latest_rsvp.latest_answerid
      ORDER BY ordering
    
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