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Home/ Questions/Q 3272090
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T18:47:28+00:00 2026-05-17T18:47:28+00:00

UPDATE3 and FINAL: SOLVED thanks to Evan and meder! UPDATE2: I should clarify, I

  • 0

UPDATE3 and FINAL: SOLVED thanks to Evan and meder!

UPDATE2: I should clarify, I need function updateFilters (a,b) to be called, not created. The function exists elsewhere. Sorry for confusion.

The code below does not work as expected – udpateFilters(a,b) is being called before for loop ends. Changing async to false solves the problem, but this does not seem right. Moreover updateFilters() is called regardless of ajax success.

What did I do wrong?

save (updateFilters(a,b));

function save (cb) {
    $.ajax ({
         url:'save.php',
         data:somedata,
         async:true,
         success: function (response) {
             for (var i in response) {}

             if (typeof cb!='undefined') cb;
    });
}

function updateFilters (a,b) {
//do some stuff here
}

ANSWER:
So as meder suggested I change the parameter. This is 2/3 of the answer!

save (
    (function (a,b) {
        return function () {
            return updateFilters(a,b);
        }
    })(a,b)
);

Now change the following:

if (typeof cb!='undefined') cb (); //brackets are important!

And good to go!

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  1. Editorial Team
    Editorial Team
    2026-05-17T18:47:29+00:00Added an answer on May 17, 2026 at 6:47 pm

    You are passing the invocation of a function, not a function that should be called at a later point. If you want the latter, do this:

    save (
       (function(a,b){
          return function() {
            return updateFilters(a,b)
          }
       })(a,b)
    );
    
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