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Home/ Questions/Q 7648753
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T10:47:46+00:00 2026-05-31T10:47:46+00:00

URL url = new URL(http://www.site.com/1.xml); SAXParserFactory factory = SAXParserFactory.newInstance(); SAXParser parser = factory.newSAXParser(); XMLHandler

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URL url = new URL("http://www.site.com/1.xml");
SAXParserFactory factory = SAXParserFactory.newInstance();
SAXParser parser = factory.newSAXParser();
XMLHandler handler = new XMLHandler();
parser.parse(url.openStream(),handler);

Because 1.xml contains invalid XML characters, parser will throw exceptions, such as An invalid XML character (Unicode: 0x1d) was found in the CDATA section.
but if I read the 1.xml into a String and filter all invalid characters, string can’t be the argument of parser.parse() method.
what can I do ?

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  1. Editorial Team
    Editorial Team
    2026-05-31T10:47:47+00:00Added an answer on May 31, 2026 at 10:47 am

    Looks like you can use java.io.StringReader to make a Reader from your string, then construct an org.xml.sax.InputSource using the StringReader. There’s a version of parse() that takes an InputSource argument.

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