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Home/ Questions/Q 6027643
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T04:37:22+00:00 2026-05-23T04:37:22+00:00

url_params = {} for i in t: try: url_params[i] = t.next() except: url_params[i] =

  • 0
url_params = {}
for i in t:
    try:
        url_params[i] = t.next()
    except:
        url_params[i] = None

Because this just looks silly to me. I’m converting a list to a dict by pairing up neighboring elements. There are cases, however, where I won’t always have a pair. The tailing element is still important but it’s value isn’t important.

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  1. Editorial Team
    Editorial Team
    2026-05-23T04:37:22+00:00Added an answer on May 23, 2026 at 4:37 am

    This is more easily done like this:

    from itertools import izip_longest
    url_params = dict(izip_longest(*[iter(t)] * 2))
    

    Example: For t = range(11), this produces

    {0: 1, 2: 3, 4: 5, 6: 7, 8: 9, 10: None}
    
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