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Home/ Questions/Q 6615047
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T20:24:51+00:00 2026-05-25T20:24:51+00:00

urls with 2 request params: /prefix1/1/ /prefix2/2/ /prefix1/1/prefix2/2 /prefix2/2/prefix1/1 url( ur’^prefix1/(?P<p1>\d+)/$’, ‘app.views.view’ ), url(

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urls with 2 request params:

/prefix1/1/
/prefix2/2/
/prefix1/1/prefix2/2
/prefix2/2/prefix1/1

url( ur'^prefix1/(?P<p1>\d+)/$', 'app.views.view' ),
url( ur'^prefix2/(?P<p2>\d+)/$', 'app.views.view' ),
url( ur'^prefix1/(?P<p1>\d+)/prefix2/(?P<p2>\d+)/$', 'app.views.view' ),
url( ur'^prefix2/(?P<p2>\d+)/prefix1/(?P<p1>\d+)/$', 'app.views.view' ),

Is possible to do this more ‘DRY’ (with 3 request params, lines in urls.py = 15) ?

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  1. Editorial Team
    Editorial Team
    2026-05-25T20:24:52+00:00Added an answer on May 25, 2026 at 8:24 pm

    I hacked together a sample and, if lazerscience’s comment doesn’t do it for you, here’s what I came up with:

    url(r'^(?P<param1>foo|bar)(/(?P<param2>\d+))?(/(?P<param3>\d+))?(/(?P<param4>\d+))?/$', 'demo.views.view'),
    

    And my view looked like:

    def view(request, *args, **kwargs):
        return render_to_response("index.html",
            { 'dict': [(k, v) for k,v in kwargs.iteritems()] },
            context_instance=RequestContext(request))
    

    It progressively added parameters as you added to the url, left to right, just as you’d expect.

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