Question

/* user-defined exception class derived from a standard class for exceptions*/  class MyProblem : public std::exception {  public:      ...      MyProblem(...) { //special constructor     }      virtual const char* what() const throw() {     //what() function     ...     }  };  ...  void f() { ...  //create an exception object and throw it  throw MyProblem(...);  ...   } 

My question is why there is a ‘const throw()’ after what()? Normally,if there is a throw() , it implies that the function before throw() can throw exception.However ,why there is a throw here?

Answer 1

Empty braces in 'throw()' means the function does not throw.