Question

Using ActionScript 3, suppose I have an array of numbers, lets say: 1, 2, 3, 4, 5. Is there a way to easily search this array and return the index corresponding to an element that is >= 2.5 (which would be, 3, in this case), for example? I’m implementing this with a while and for loop, and seems pretty wordy. Thought there might be a method for this already, but haven’t stumbled upon it in:

http://help.adobe.com/en_US/FlashPlatform/reference/actionscript/3/Array.html#every()

Otherwise, what would be a simple way to achieve it?

In case it helps, I’ll use this to implement a straight-forward linear interpolation math routine, assuming one doesn’t already exist I’m not aware of.

Answer 1

I’m not aware of any firstIndexOf in ActionScript.

You could add it to an ArrayUtil class:

Given the array:

var array:Array = [ 1, 2, 3, 4, 5 ];

Pass it to the ArrayUtil function:

public static function firstIndexOf(array:Array, value:Number):int
{
    for(var i:uint = 0; i < array.length; i++)
    {
        if(array[i] >= value)
            return i;
    }

    // if not found, return -1
    return -1;
}